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CHM 101 CHM 101 Past Questions Objective Question
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Question

A 20.00 mL sample of a KOH solution is titrated with 15.00 mL of 0.100 M H₂SO₄ to the equivalence point. What is the concentration of the KOH solution?
Options
A 0.0750 M
B 0.100 M
C 0.150 M
Correct Answer
D 0.200 M
Correct Answer

Option C is the correct answer.

Detailed Explanation

Balanced equation: 2KOH + H₂SO₄ → K₂SO₄ + 2H₂O. Moles H₂SO₄ = 0.01500 L × 0.100 M = 0.001500 mol. Moles KOH = 2 × 0.001500 = 0.003000 mol. Concentration KOH = 0.003000 mol / 0.02000 L = 0.150 M.

Hint

Pay attention to the 2:1 mole ratio between KOH and H₂SO₄.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1350 of 1872
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