Question Detail
Question
For the reaction 2A + B → C, the rate law is rate = k[A][B]². If the concentration of B is doubled while keeping [A] constant, the rate will increase by a factor of:
Correct Answer
Option B is the correct answer.
Detailed Explanation
Initial rate = k[A][B]². If [B] doubles, new rate = kA² = k[A] × 4[B]² = 4 × k[A][B]². Factor = 4.
Hint
The rate is proportional to [B]², so doubling B increases the rate by a factor of 2² = 4.