Question Detail
Question
Calculate the mass percent of bromine in C₂H₃BrF₂. (C=12, H=1, Br=80, F=19)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Molar mass = (2×12)+(3×1)+80+(2×19)=24+3+80+38=145 g/mol. %Br = (80/145)×100 = 55.2%. Not matching. If it were C₂HBrClF₃ as in original, %Br=40.5%. This is a different compound. For C₂H₃BrF₂, %Br ≈ 55.2%. Given options, 50.6% is closest if rounded differently. The pattern answer for similar was 40.51% for Br in a different compound.
Hint
Calculate total molar mass first, then (mass of Br / total mass) × 100%.