Question Detail
Question
For the equilibrium: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g); ΔH = -198 kJ mol⁻¹. Which of the following changes will decrease the proportion of SO₃ at equilibrium?
Correct Answer
Option B is the correct answer.
Detailed Explanation
The reaction is exothermic (ΔH negative). Increasing temperature favors the endothermic reverse reaction, decreasing SO₃. Pressure favors the side with fewer gas moles (forward, 3→2), so increasing pressure increases SO₃.
Hint
Apply Le Chatelier's principle: treat heat as a product for exothermic reactions.