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CHM 101 CHM 101 Past Questions Objective Question
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Question

For the reaction: 2N₂O₅(g) → 4NO₂(g) + O₂(g), the rate of appearance of NO₂ is 4.0 × 10⁻³ M/s. What is the rate of disappearance of N₂O₅?
Options
A 1.0 × 10⁻³ M/s
B 2.0 × 10⁻³ M/s
Correct Answer
C 4.0 × 10⁻³ M/s
D 8.0 × 10⁻³ M/s
Correct Answer

Option B is the correct answer.

Detailed Explanation

From stoichiometry, 2 mol N₂O₅ produce 4 mol NO₂. The rate of disappearance of N₂O₅ = (2/4) × rate of appearance of NO₂ = 0.5 × 4.0 × 10⁻³ = 2.0 × 10⁻³ M/s.

Hint

Use the stoichiometric coefficients: (1/2)(-Δ[N₂O₅]/Δt) = (1/4)(Δ[NO₂]/Δt).

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1419 of 1872
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