Question Detail
Question
If 36.0 g of glucose (C₆H₁₂O₆) is combusted completely, what mass of water is produced? (C=12, H=1, O=16)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Balanced: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O. Molar mass glucose = 180 g/mol. Moles glucose = 36.0/180 = 0.200 mol. Moles H₂O = 6 × 0.200 = 1.20 mol. Mass H₂O = 1.20 × 18 = 21.6 g.
Hint
1 mole of glucose produces 6 moles of water.