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CHM 101 CHM 101 Past Questions Objective Question
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Question

Naturally occurring boron consists of 19.9% boron-10 (10.013 amu) and 80.1% boron-11 (11.009 amu). Calculate the average atomic mass of boron.
Options
A 10.81
Correct Answer
B 10.50
C 11.00
D 10.01
Correct Answer

Option A is the correct answer.

Detailed Explanation

Average = (0.199 × 10.013) + (0.801 × 11.009) = 1.9926 + 8.8182 = 10.8108 ≈ 10.81.

Hint

Multiply each isotope's mass by its fractional abundance and sum.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1433 of 1872
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