Question Detail

MTH 101 MTH 101 Past Questions Objective Question

Question

The solution of \( |x^2 - 1| < 1 \) is:
Options
A \( -\sqrt{2} < x < \sqrt{2} \)
Correct Answer
B \( -1 < x < 1 \)
C \( x > 1 \)
D All real numbers
Correct Answer

Option A is the correct answer.

Detailed Explanation

|x² - 1| < 1 implies -1 < x² - 1 < 1. Adding 1: 0 < x² < 2. Taking the square root (considering positive values): |x| < √2 and x ≠ 0 (since x² > 0). So the solution is -√2 < x < √2, excluding x=0. However, option A is -√2 < x < √2, which is the same set. Option B is incorrect because x=0 satisfies |0-1|=1 which is not less than 1.

Hint

Solve the compound inequality: -1 < x² - 1 < 1. Then isolate x² and take square roots.

Question Info