Question Detail

MTH 101 MTH 101 Past Questions Objective Question

Question

Evaluate \(\cos(-225^\circ)\) without the use of e-calculator or figures tables.
Options
A \(\frac{\sqrt{2}}{2}\)
Correct Answer
B \(\frac{\sqrt{3}}{2}\)
C \(\sqrt{3}\)
D \(\frac{\sqrt{3}}{3}\)
Correct Answer

Option A is the correct answer.

Detailed Explanation

(\cos(-225^\circ) = \cos(225^\circ)) because cosine is even. (225^\circ = 180^\circ + 45^\circ), so (\cos(225^\circ) = -\cos(45^\circ) = -\frac{\sqrt{2}}{2}). Wait, that gives negative. Let's recalc: (\cos(-225^\circ) = \cos(225^\circ) = \cos(180^\circ+45^\circ) = -\cos45^\circ = -\frac{\sqrt{2}}{2}). That is not among the options. However, (\sin(-225^\circ) = \frac{\sqrt{2}}{2}). Possibly the question meant (\sin(-225^\circ)). Given the options, (\frac{\sqrt{2}}{2}) is the answer for sine. Assuming a misprint, A is the likely intended answer.

Hint

Use \(\cos(-\theta) = \cos\theta\) and reference angles.

Question Info