Question Detail
Question
Find the sum of the terms of the infinite geometric progression: \(\frac{1}{3}, \frac{1}{9}, \frac{1}{27}, \ldots\)
Correct Answer
Option A is the correct answer.
Detailed Explanation
First term a = 1/3, common ratio r = 1/3. Sum to infinity = a/(1-r) = (1/3)/(1 - 1/3) = (1/3)/(2/3) = 1/2 = 0.5. 3/8 = 0.375, 3/6=0.5, so B is 0.5. Option B is 3/6 = 1/2. So B is correct.
Hint
Sum to infinity = a/(1-r) for |r|<1.