Question Detail

MTH 101 MTH 101 Past Questions Objective Question
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Question

Find the common ratio and the 6th term of the GP: \(-\frac{1}{2}, \frac{1}{8}, -\frac{1}{32}, \ldots\)
Options
A \(-\frac{1}{4}, -\frac{1}{1024}\)
B \(-\frac{1}{4}, \frac{1}{512}\)
C \(-\frac{1}{4}, -\frac{1}{2048}\)
Correct Answer
D \(-\frac{1}{4}, -\frac{1}{1024}\)
Correct Answer

Option C is the correct answer.

Detailed Explanation

Common ratio r = (1/8)/(-1/2) = (1/8)(-2) = -1/4. First term a = -1/2. 6th term = a * r^5 = (-1/2)(-1/4)^5 = (-1/2)*(-1/1024) = 1/2048.

Hint

r = second term / first term. nth term = a * r^(n-1).

Question Info

Course: MTH 101
Topic: MTH 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 613 of 696
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