Question Detail

MTH 101 MTH 101 Past Questions Objective Question
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Question

Given that \(k-2, k-1\) and \(3k-5\) are three consecutive terms of an A.P. Find the possible values of k.
Options
A \(\frac{5}{2}\)
Correct Answer
B 2
C 5
D 3
Correct Answer

Option A is the correct answer.

Detailed Explanation

For an AP, 2(k-1) = (k-2) + (3k-5) ⇒ 2k-2 = 4k-7 ⇒ -2k = -5 ⇒ k = 5/2.

Hint

For three consecutive terms of an AP, the middle term is the average: 2b = a + c.

Question Info

Course: MTH 101
Topic: MTH 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 634 of 696
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