Question Detail

MTH 101 MTH 101 Past Questions Objective Question
Take CBT

Question

The sum \(1^3 + 2^3 + 3^3 + \ldots + n^3\) gives
Options
A \(\left[\frac{n(n+1)}{2}\right]^2\)
Correct Answer
B \(\left[\frac{(n+1)(n+2)}{6}\right]^2\)
C \(\left[\frac{(n+1)(n+2)}{6}\right]^2\)
D \(\frac{n(n+1)(2n+1)}{6}\)
Correct Answer

Option A is the correct answer.

Detailed Explanation

The sum of cubes formula is (\sum_{k=1}^n k^3 = \left[\frac{n(n+1)}{2}\right]^2).

Hint

Recall the formula for the sum of cubes.

Question Info

Course: MTH 101
Topic: MTH 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 664 of 696
Previous Course Details Next