Question Detail
Question
The kinetic energy of a 7.3 kg steel ball traveling at 18.0 m/s is _____ J.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Kinetic energy (KE) = ½mv² = 0.5 × 7.3 kg × (18.0 m/s)² = 0.5 × 7.3 × 324 = 3.65 × 324 = 1182.6 J ≈ 1.2 × 10³ J.
Hint
Use the formula KE = ½mv².