Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

Calculate the pH of 0.002 mol dm⁻³ solution of calcium hydroxide.
Options
A 11.30
B 11.00
C 11.60
Correct Answer
D 11.43
Correct Answer

Option C is the correct answer.

Detailed Explanation

Ca(OH)₂ is a strong base that dissociates completely: Ca(OH)₂ → Ca²⁺ + 2OH⁻. [OH⁻] = 2 × 0.002 = 0.004 M. pOH = -log[OH⁻] = -log(0.004) = -log(4 × 10⁻³) = 3 - log4 = 3 - 0.60 = 2.40. pH = 14 - pOH = 14 - 2.40 = 11.60.

Hint

Remember that calcium hydroxide produces 2 OH⁻ ions per formula unit.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1658 of 1872
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