Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

Which statement is true for the reaction: Cr₂O₇²⁻ + 3HSO₃⁻ + 8H⁺ → 2Cr³⁺ + 3SO₄²⁻ + 5H₂O?
Options
A Cr₂O₇²⁻ is the reducing agent
B HSO₃⁻ acts as the oxidizing agent
C Oxidation of HSO₃⁻ occurs to give SO₄²⁻
Correct Answer
D Oxidation of Cr₂O₇²⁻ occurs to give Cr³⁺
Correct Answer

Option C is the correct answer.

Detailed Explanation

In this reaction, sulfur in HSO₃⁻ has an oxidation state of +4 and is oxidized to +6 in SO₄²⁻. Therefore, HSO₃⁻ is the reducing agent and undergoes oxidation. Cr in Cr₂O₇²⁻ is reduced from +6 to +3, so it is the oxidizing agent.

Hint

Determine the oxidation states of Cr and S to see which is oxidized and which is reduced.

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1661 of 1872
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