Question Detail
Question
For the reaction C₆H₁₄(g) → C₆H₆(g) + 4H₂(g), DP(H₂)/Dt was found to be 2.5 × 10⁻² atm/s, where DP(H₂) is the change in pressure of hydrogen. Determine DP(C₆H₁₄)/Dt for this reaction at the same time.
Correct Answer
Option B is the correct answer.
Detailed Explanation
From the stoichiometry: for every 4 moles of H₂ produced, 1 mole of C₆H₁₄ is consumed. Therefore, the rate of consumption of C₆H₁₄ is 1/4 the rate of formation of H₂. DP(C₆H₁₄)/Dt = -(1/4) × DP(H₂)/Dt = -(1/4) × (2.5 × 10⁻²) = -6.25 × 10⁻³ atm/s ≈ -6.2 × 10⁻³ atm/s.
Hint
Use the stoichiometric coefficients to relate the rates of change of reactants and products.