Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

Calculate the change in entropy for the reaction (ΔS°): 2 SO₂(g) + O₂(g) → 2 SO₃(g) given ΔS°(SO₂(g)) = 248.2 J/mol/K, ΔS°(O₂(g)) = 205.0 J/mol/K and ΔS°(SO₃(g)) = 256.8 J/mol/K
Options
A ΔS° = -187.8 J/mol/K
Correct Answer
B ΔS° = 196.4 J/mol/K
C ΔS° = 187.8 J/mol/K
D ΔS° = -196.4 J/mol/K
Correct Answer

Option A is the correct answer.

Detailed Explanation

ΔS° = Σ S°(products) - Σ S°(reactants) = [2 × 256.8] - [(2 × 248.2) + 205.0] = 513.6 - (496.4 + 205.0) = 513.6 - 701.4 = -187.8 J/mol/K.

Hint

ΔS° = Σ S°(products) - Σ S°(reactants).

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1701 of 1872
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