Question Detail

CHM 101 CHM 101 Past Questions Objective Question
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Question

What is the correct reduction half-equation from the reaction?
Options
A Fe²⁺ → Fe³⁺ + e⁻
B Mn²⁺ → MnO₄⁻ + 5e⁻
C MnO₄⁻ → Mn²⁺ + 8H⁺ + 5e⁻
D MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Reduction involves gain of electrons. The permanganate ion (MnO₄⁻) gains 5 electrons to become Mn²⁺, with H⁺ and H₂O balancing the equation.

Hint

Reduction half-equation has electrons on the left (reactant side).

Question Info

Course: CHM 101
Topic: CHM 101 Past Questions
Type: Objective
Difficulty: Not specified
Question 1722 of 1872
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