Question Detail

CHM 101 CHM 101 Past Questions Objective Question

Question

A certain sample contains 4.86 moles of calcium carbonate. What is the mass of calcium carbonate [Ca = 40, C = 12, O = 16]?
Options
A 122g
B 243 g
C 486 g
Correct Answer
D 927 g
Correct Answer

Option C is the correct answer.

Detailed Explanation

Molar mass CaCO₃ = 40+12+(3×16)=100 g/mol. Mass = 4.86 mol × 100 g/mol = 486 g.

Hint

Mass = moles × molar mass.

Question Info