Question Detail
Question
The specific heat capacity of olive oil is 2.2 J/°C/g. How much energy, in kJ, is required to raise the temperature of 48 g of olive oil from 23°C to 145°C?
Correct Answer
Option B is the correct answer.
Detailed Explanation
q = m × c × ΔT = 48 g × 2.2 J/g°C × (145-23)°C = 48 × 2.2 × 122 = 48 × 268.4 = 12,883.2 J = 12.9 kJ.
Hint
q = mcΔT. Convert J to kJ.