Question Detail
Question
A certain sample contains 4.86 moles of calcium carbonate. What is the mass of carbonate ions [Ca = 40, C = 12, O = 16]?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Moles of CO₃²⁻ = moles of CaCO₃ = 4.86 mol. Molar mass CO₃²⁻ = 12 + 48 = 60 g/mol. Mass = 4.86 × 60 = 291.6 g ≈ 292 g.
Hint
Each CaCO₃ yields one CO₃²⁻ ion.