Question Detail

CHM 102 Fundamentals of Alkanes: Properties and Preparation Methods Objective Question
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Question

In Kolbe's electrolytic method, the electrolysis of sodium salt of a monocarboxylic acid produces:
Options
A An alkane with same number of carbons
B An alkane with one less carbon
C A higher alkane (R-R)
Correct Answer
D An alkene
Correct Answer

Option C is the correct answer.

Detailed Explanation

Kolbe electrolysis couples two alkyl radicals to form a higher alkane: 2RCOONa → R-R + 2CO2 + 2e-.

Hint

It's like an electrolytic Wurtz reaction.

Question Info

Course: CHM 102
Topic: Fundamentals of Alkanes: Properties and Preparation Methods
Type: Objective
Difficulty: Not specified
Question 74 of 1999
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