Question Detail

CHM 102 Alkynes: Structure, Bonding, and Nomenclature Objective Question
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Question

What is the product when 1-butyne is treated with NaNH2 in liquid NH3?
Options
A No reaction
B Sodium butylide (CH3CH2CH2CH2Na)
C Sodium 1-butynide (CH3CH2C≡CNa)
Correct Answer
D 1-Butene
Correct Answer

Option C is the correct answer.

Detailed Explanation

NaNH2 is a strong base that deprotonates the terminal alkyne to form the sodium acetylide (sodium 1-butynide) with liberation of NH3.

Hint

Terminal hydrogen is removed.

Question Info

Course: CHM 102
Topic: Alkynes: Structure, Bonding, and Nomenclature
Type: Objective
Difficulty: Not specified
Question 196 of 1999
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