Question Detail
Question
In the acidic cleavage of an unsymmetrical ether like CH3OCH2CH3 with HI, which product is formed in greater amount?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Acidic cleavage of an unsymmetrical ether with HI gives the alkyl iodide from the less hindered (primary) carbon via SN2, and alcohol from the other side. So ethyl iodide and methanol.
Hint
Iodide attacks less hindered carbon.