Question Detail

CHM 102 Alkynes: Structure, Bonding, and Nomenclature Objective Question
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Question

What is the product when 1‑butyne is treated with NaNH₂ in liquid NH₃?
Options
A No reaction
B Sodium butylide (CH₃CH₂CH₂CH₂Na)
C Sodium 1‑butynide (CH₃CH₂C≡CNa)
Correct Answer
D 1‑Butene
Correct Answer

Option C is the correct answer.

Detailed Explanation

NaNH₂ is a strong base that deprotonates the terminal alkyne to form the sodium acetylide, liberating NH₃.

Hint

Terminal hydrogen is removed.

Question Info

Course: CHM 102
Topic: Alkynes: Structure, Bonding, and Nomenclature
Type: Objective
Difficulty: Not specified
Question 556 of 1999
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