Question Detail
Question
A 0.2-m wire moves at 5 m/s at 30° to a 0.4-T field. What is the induced emf?
Correct Answer
Option A is the correct answer.
Detailed Explanation
ε = B L v sin θ = (0.4 T)(0.2 m)(5 m/s)(sin 30°) = (0.4)(0.2)(5)(0.5) = 0.2 V.
Hint
sin 30° = 0.5.