Question Detail
Question
If a wire of length 0.5 m moves at 8 m/s perpendicular to a 0.2-T field, what is the induced emf?
Correct Answer
Option A is the correct answer.
Detailed Explanation
ε = B L v = (0.2 T)(0.5 m)(8 m/s) = 0.8 V.
Hint
Multiply B × L × v.