Question Detail

PHY 102 Gauss's Law and Electrostatic Fields Objective Question
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Question

What is the capacitance of a parallel plate capacitor with plate area A and separation d?
Options
A C = ε₀A/d
Correct Answer
B C = ε₀d/A
C C = A/(ε₀d)
D C = ε₀A/d²
Correct Answer

Option A is the correct answer.

Detailed Explanation

For a parallel plate capacitor, C = Q/V. With Q = σA and V = Ed = (σ/ε₀)d, we get C = ε₀A/d.

Hint

Capacitance increases with area, decreases with separation.

Question Info

Course: PHY 102
Topic: Gauss's Law and Electrostatic Fields
Type: Objective
Difficulty: Not specified
Question 57 of 1819
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