Question Detail

PHY 102 Gauss's Law and Electrostatic Fields Objective Question

Question

What is the electric field in the region between two large parallel conducting plates with equal and opposite surface charge densities ±σ?
Options
A E = σ/(2ε₀)
B E = σ/ε₀
Correct Answer
C E = 2σ/ε₀
D E = 0
Correct Answer

Option B is the correct answer.

Detailed Explanation

The fields from the two oppositely charged plates add between the plates: E = σ/(2ε₀) + σ/(2ε₀) = σ/ε₀. Outside, they cancel.

Hint

Fields reinforce between plates.

Question Info