Question Detail
Question
In an RC discharging circuit, after one time constant (t = RC), the capacitor voltage falls to what percentage of its initial value?
Correct Answer
Option C is the correct answer.
Detailed Explanation
V = V₀ e⁻¹ = V₀ × 0.368 ≈ 37% of the initial value.
Hint
1/e ≈ 0.37.