Question Detail
Question
The permittivity of free space (ε₀) appears in the denominator of Gauss's Law. If ε₀ were larger, the flux for the same charge would be:
Correct Answer
Option B is the correct answer.
Detailed Explanation
Flux ΦE = Q/ε₀; therefore, increasing the denominator (ε₀) would result in a smaller flux value for a constant Q.
Hint
Check the inverse relationship in the formula.