Question Detail
Question
Evaluate the limit of \( \frac{x^3 - 8}{x^2 - 4} \) as \( x \) tends to 2.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Factor ( (x^3-8) = (x-2)(x^2+2x+4) ) and ( (x^2-4) = (x-2)(x+2) ). Cancel ( (x-2) ) and substitute ( x=2 ) to get ( \frac{12}{4} = 3 ).
Hint
Example 4 factorisation.