Question Detail

MTH 102 Limits Objective Question

Question

In the rationalisation method for limits involving square roots, what is the conjugate of \( 2 - \sqrt{x - 3} \)?
Options
A \( 2 - \sqrt{x + 3} \)
B \( 2 + \sqrt{x - 3} \)
Correct Answer
C \( -2 - \sqrt{x - 3} \)
D \( \sqrt{x - 3} - 2 \)
Correct Answer

Option B is the correct answer.

Detailed Explanation

The conjugate of a term involving a square root is found by changing the sign between the two terms.

Hint

Example 5 methodology.

Question Info