Question Detail
Question
Evaluate the limit of \( \frac{x^3 - x^2 - x - 2}{x^3 - 8} \) as \( x \) tends to 2.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Factoring out ( (x-2) ) from both numerator and denominator leaves ( \frac{x^2 + x + 1}{x^2 + 2x + 4} ). At ( x=2 ), this is ( \frac{7}{12} ).
Hint
Model Question 21.