Question Detail
Question
Evaluate the limit of \( \frac{2x}{\sqrt{x^2 + 1}} \) as \( x \) tends to infinity.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Dividing by ( x ), we get ( \frac{2}{\sqrt{1 + 1/x^2}} ). At infinity, this is ( \frac{2}{1} = 2 ).
Hint
Exercise 1.1, Question 17.