Question Detail
Question
What is the limit of \( \frac{e^{\cos x} + e^{\sin 2x}}{e^{\cos x} + e^{-\sin 2x}} \) as \( x \) approaches \( \frac{\pi}{2} \)?
Correct Answer
Option A is the correct answer.
Detailed Explanation
At ( x = \frac{\pi}{2} ), ( \cos x = 0 ) and ( \sin 2x = 0 ). The expression becomes ( \frac{e^0 + e^0}{e^0 + e^0} = \frac{2}{2} = 1 ).
Hint
Exercise 1.1, Question 24.