Question Detail
Question
Evaluate the limit of \( \frac{x^3 - x^2 - x + 1}{x^3 - 2x^2 + x} \) as \( x \) tends to 1.
Correct Answer
Option A is the correct answer.
Detailed Explanation
Applying L'Hospital's Rule twice results in ( \frac{6x-2}{6x-4} ). At ( x=1 ), this is ( \frac{4}{2} = 2 ).
Hint
Example 11.