Question Detail

MTH 102 Limits Objective Question

Question

Evaluate the limit of \( \frac{\sin 3x}{\sin 2x} \) as \( x \) approaches 0.
Options
A 1
B \(\frac{3}{2}\)
Correct Answer
C \(\frac{2}{3}\)
D 0
Correct Answer

Option B is the correct answer.

Detailed Explanation

Using L'Hospital's rule: ( \frac{3\cos 3x}{2\cos 2x} ). At ( x=0 ), this is ( \frac{3}{2} ).

Hint

Trigonometric coefficients.

Question Info