Question Detail
Question
Evaluate the limit of \( \frac{x^2 - 9}{x + 3} \) as \( x \) tends to -3.
Correct Answer
Option B is the correct answer.
Detailed Explanation
Factor as ( \frac{(x-3)(x+3)}{x+3} ). Limit is ( x-3 ), so ( -3-3 = -6 ).
Hint
Factorisation.