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PHY 102 Test Compilation PHY 102 1 Objective Question

Question

The resonant frequency of a circuit is 1000KHz. If each of the capacitance and inductance in the circuit is reduced by 50% and no other changes are made, the resonant frequency will become
Options
A 1000KHz
B 2000KHz
Correct Answer
C 100.0KHz
D 200.0KHz
Correct Answer

Option B is the correct answer.

Detailed Explanation

f = 1/(2π√(LC)). If L→L/2 and C→C/2, then LC→LC/4, √(LC)→½√(LC), so f doubles to 2000 kHz.

Hint

f ∝ 1/√(LC). Halving both L and C doubles f.

Question Info