Question Detail
Question
galvanometer of 50 Ω gives full scale deflection with 2 mA current. To convert it into ammeter, range of 10 A is connected with it, shunt resistance should be
Correct Answer
Option C is the correct answer.
Detailed Explanation
V_g = I_g R_g = 0.002 × 50 = 0.1 V. Shunt current I_sh = I - I_g = 10 - 0.002 = 9.998 A. R_sh = V_g/I_sh = 0.1/9.998 ≈ 0.01 Ω.
Hint
R_sh = (I_g R_g)/(I - I_g).