Question Detail

PHY 102 Test Compilation PHY 102 2 Objective Question
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Question

240V a.c source across pure 1.0H inductor, frequency 60 Hz. Current?
Options
A 2/π A
Correct Answer
B 2 A
C π/2 A
D 2π A
Correct Answer

Option A is the correct answer.

Detailed Explanation

X_L = 2πfL = 2π×60×1 = 120π ≈ 377 Ω. I = V/X_L = 240/(120π) = 2/π A.

Hint

I = V/(2πfL).

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 2
Type: Objective
Difficulty: Not specified
Question 234 of 1819
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