Question Detail
Question
capacitor 22µF, resistor 200Ω, series across 12V 50Hz. Impedance?
Correct Answer
Option D is the correct answer.
Detailed Explanation
X_C = 1/(2πfC) = 1/(2π×50×22e-6) = 1/(0.006908) ≈ 144.7 Ω. Z = √(R² + X_C²) = √(200² + 144.7²) = √(40000 + 20946) = √60946 ≈ 246.9 Ω.
Hint
Z = √(R² + X_C²).