Question Detail
Question
Find the electric field intensity at a distance of 20 cm from a charge of 2 nC.
Correct Answer
Option D is the correct answer.
Detailed Explanation
E = kq/r² = (9×10⁹)(2×10⁻⁹)/(0.2)² = 18/(0.04) = 450 N/C.
Hint
E = kq/r².