Question Detail

PHY 102 Test Compilation PHY 102 3 Objective Question
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Question

Determine the force on an electron of charge 1.6 × 10⁻¹⁹ C placed in a uniform electric field of 120,000 V/m.
Options
A 0 N
B 1.92 × 10⁻¹⁴ N
Correct Answer
C 1.92 × 10¹² N
D 1.92 × 10 N
Correct Answer

Option B is the correct answer.

Detailed Explanation

F = qE = (1.6×10⁻¹⁹)(1.2×10⁵) = 1.92×10⁻¹⁴ N.

Hint

F = qE.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 3
Type: Objective
Difficulty: Not specified
Question 299 of 1819
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