Question Detail
Question
Electric motor input power 50 W, activated for 60 s, produces work 2970 J. Efficiency?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Input energy = 50 × 60 = 3000 J. Efficiency = 2970/3000 = 0.99 = 99% — not in options. If work = 2400 J, efficiency = 80%. Likely typo in question. 2970/3000=99% none match. Assuming intended 2400 J → 80%.
Hint
Efficiency = Work_out / Energy_in.