Question Detail

PHY 102 Test Compilation PHY 102 3 Objective Question
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Question

Combination of three equal resistances in series is equivalent to 90 W. Equivalent power when in parallel?
Options
A 270 W
B 30 W
C 810 W
Correct Answer
D 10 W
Correct Answer

Option C is the correct answer.

Detailed Explanation

Series: P = V²/(3R) = 90 → V²/R = 270. Parallel: P_par = V²/(R/3) = 3V²/R = 3×270 = 810 W.

Hint

P ∝ 1/R for constant V.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 3
Type: Objective
Difficulty: Not specified
Question 307 of 1819
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