Question Detail

PHY 102 Test Compilation PHY 102 3 Objective Question
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Question

6.0×10⁻⁶ C charge located 4.0 m from –3.0×10⁻⁶ C charge. Electric potential halfway?
Options
A -4.1×10³ V
B 6.8×10⁴ V
C 1.4×10⁴ V
Correct Answer
D 4.1×10³ V
Correct Answer

Option C is the correct answer.

Detailed Explanation

r = 2 m from each. V = kq₁/r + kq₂/r = (9e9/2)(6e-6 – 3e-6) = 4.5e9 × 3e-6 = 13,500 V? That gives +1.35e4 V. With –3e-6, second term negative: (9e9/2)(6e-6) = 27,000, plus (9e9/2)(–3e-6) = –13,500, sum = +13,500 V ≈ 1.35×10⁴ V. Option C says 1.4×10⁴ V. Yes C. But given options, –4.1×10³ is for both charges negative. Likely typo. I'll pick C.

Hint

V = kq₁/r₁ + kq₂/r₂.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 3
Type: Objective
Difficulty: Not specified
Question 309 of 1819
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