Question Detail

PHY 102 Test Compilation PHY 102 3 Objective Question

Question

What must the charge (sign and magnitude) of a particle of mass 5 g be for it to remain stationary in downward E = 800 N/C?
Options
A -30.6 μC
B -61.3 μC
Correct Answer
C +61.3 μC
D -30.6 μC
Correct Answer

Option B is the correct answer.

Detailed Explanation

Weight = mg = 0.005×9.8 = 0.049 N downward. For equilibrium, electric force upward → q negative (since E downward). qE = mg → q = mg/E = 0.049/800 = 6.125×10⁻⁵ C = 61.25 μC. So q = –61.25 μC. Options: –61.3 μC not listed? A and D both –30.6. Likely half value. Given options, closest is –61.3 but missing. I'll pick B if corrected. But B says –61.3? Actually B shows –61.3? No B shows –61.3? Let me re-check: A: -30.6, B: -61.3, C: +61.3, D: -30.6. Correct is –61.3 μC → B.

Hint

qE = mg, sign opposite to E.

Question Info